Let's simplify the inequality step by step:

Expand the left side of the inequality:
$3x-8$$3x+8$ = 9x^2 - 64

Expand the right side of the inequality:
$3x-5$² = 9x^2 - 30x + 25
$3x-5$² - 29 = 9x^2 - 30x + 25 - 29 = 9x^2 - 30x - 4

So the simplified inequality becomes:
9x^2 - 64 ≤ 9x^2 - 30x - 4

Now, let's solve for x:

Subtract 9x^2 from both sides:
-64 ≤ -30x - 4

Add 4 to both sides:
-60 ≤ -30x

Divide by -30 $rememberingtoswitchthedirectionoftheinequalitybecausewearedividingbyanegativenumber$:
2 ≥ x

So the solution to the inequality $3x-8$$3x+8$≤ $3x-5$²-29 is x ≤ 2.