To solve the equation $49\times 23+\frac{3920}{28}=\frac{167400}{27}-91\times 62$, we can calculate each part step by step.

Left Side:

Calculate $49\times 23$:
$$49\times 23=1127$$

Calculate $\frac{3920}{28}$:
$$3920÷28=140$$

Now add the results from step 1 and step 2:
$$1127+140=1267$$

Right Side:

Calculate $\frac{167400}{27}$:
$$167400÷27=6200$$

Calculate $91\times 62$:
$$91\times 62=5642$$

Now subtract the result from step 2 from the result from step 1:
$$6200-5642=558$$

Now we have: $$1267=558$$

This equation does not hold true. Therefore, $49\times 23+\frac{3920}{28}\ne \frac{167400}{27}-91\times 62$.