To solve this system of equations, we can use the method of substitution or elimination. Let's use the elimination method.
We have the equations:
We can multiply the first equation by 5 to match the coefficients of x in both equations:
5(x + 2y) = 5(11)5x + 10y = 55
Now, we have the equations:
Subtract the second equation from the first equation to eliminate x:
(5x + 10y) - (5x - 3y) = 55 - 35x + 10y - 5x + 3y = 5213y = 52y = 4
Now, substitute y = 4 into the first equation to solve for x:
x + 2(4) = 11x + 8 = 11x = 3
Therefore, the solution to the system of equations is x = 3 and y = 4.
To solve this system of equations, we can use the method of substitution or elimination. Let's use the elimination method.
We have the equations:
x + 2y = 115x - 3y = 3We can multiply the first equation by 5 to match the coefficients of x in both equations:
5(x + 2y) = 5(11)
5x + 10y = 55
Now, we have the equations:
5x + 10y = 555x - 3y = 3Subtract the second equation from the first equation to eliminate x:
(5x + 10y) - (5x - 3y) = 55 - 3
5x + 10y - 5x + 3y = 52
13y = 52
y = 4
Now, substitute y = 4 into the first equation to solve for x:
x + 2(4) = 11
x + 8 = 11
x = 3
Therefore, the solution to the system of equations is x = 3 and y = 4.