Expanding both sides of the equation:

(2x+3)(3x+1) + (5x+2)(2x+5) = 4x-1

First, expand the left side:

(2x+3)(3x+1) = 6x^2 + 2x + 9x + 3 = 6x^2 + 11x + 3

(5x+2)(2x+5) = 10x^2 + 25x + 4x + 10 = 10x^2 + 29x + 10

Combining the two expanded expressions:

6x^2 + 11x + 3 + 10x^2 + 29x + 10 = 4x - 1

Simplifying the equation:

16x^2 + 40x + 13 = 4x - 1

Rearranging the terms to set it equal to zero:

16x^2 + 40x - 4x -1 - 13 = 0

16x^2 + 36x -14 = 0

Which simplifies further to:

8x^2 + 18x - 7 = 0

Therefore, the equation (2x+3)(3x+1) + (5x+2)(2x+5) is indeed not equal to 4x-1.