(x-4)^2 = x(x+2)(x-4)(x-4) = x(x+2)(x^2 - 4x - 4x + 16) = x^2 + 2x(x^2 - 8x + 16) = x^2 + 2xx^2 - 8x + 16 = x^2 + 2xSubtract x^2 from both sides:-8x + 16 = 2xSubtract 2x from both sides:-10x + 16 = 0Subtract 16 from both sides:-10x = -16Divide by -10:x = 1.6
Ответ: x = 1.6
(x-4)^2 = x(x+2)
(x-4)(x-4) = x(x+2)
(x^2 - 4x - 4x + 16) = x^2 + 2x
(x^2 - 8x + 16) = x^2 + 2x
x^2 - 8x + 16 = x^2 + 2x
Subtract x^2 from both sides:
-8x + 16 = 2x
Subtract 2x from both sides:
-10x + 16 = 0
Subtract 16 from both sides:
-10x = -16
Divide by -10:
x = 1.6
Ответ: x = 1.6