1) (x-12)(3x+9) = 0(x-12) = 0 => x = 12(3x+9) = 0 => 3x = -9 => x = -3
2) (x+2)² = 0(x+2) = 0 => x = -2
3) x² - 25 = 0(x+5)(x-5) = 0x+5 = 0 => x = -5x-5 = 0 => x = 5
Итак, решения уравнений:x = 12, x = -3, x = -2, x = -5, x = 5.
1) (x-12)(3x+9) = 0
(x-12) = 0 => x = 12
(3x+9) = 0 => 3x = -9 => x = -3
2) (x+2)² = 0
(x+2) = 0 => x = -2
3) x² - 25 = 0
(x+5)(x-5) = 0
x+5 = 0 => x = -5
x-5 = 0 => x = 5
Итак, решения уравнений:
x = 12, x = -3, x = -2, x = -5, x = 5.