This equation can be simplified by using the properties of absolute value and factoring.
Given the equation |2x+y-3| + 4x^2 - 4xy + y^2 = 0
First, notice that the expression inside the absolute value can be factored as (2x + y - 3).
So, the equation can be rewritten as |2x+y-3| + (2x - 3)(2x - 3) = 0
Now, since the absolute value expression is always non-negative, it must equal zero for the overall equation to hold true. Therefore, we have:
2x + y - 3 = 0=> y = -2x + 3
Now, substituting y = -2x + 3 into the second part of the equation:
(2x - 3)(2x - 3) = 0=> (2x - 3)^2 = 0=> 2x - 3 = 0=> 2x = 3=> x = 3/2
Lastly, substitute x = 3/2 back into y = -2x + 3:
y = -2(3/2) + 3=> y = -3 + 3=> y = 0
Therefore, the solution to the equation is x = 3/2 and y = 0.
This equation can be simplified by using the properties of absolute value and factoring.
Given the equation |2x+y-3| + 4x^2 - 4xy + y^2 = 0
First, notice that the expression inside the absolute value can be factored as (2x + y - 3).
So, the equation can be rewritten as |2x+y-3| + (2x - 3)(2x - 3) = 0
Now, since the absolute value expression is always non-negative, it must equal zero for the overall equation to hold true. Therefore, we have:
2x + y - 3 = 0
=> y = -2x + 3
Now, substituting y = -2x + 3 into the second part of the equation:
(2x - 3)(2x - 3) = 0
=> (2x - 3)^2 = 0
=> 2x - 3 = 0
=> 2x = 3
=> x = 3/2
Lastly, substitute x = 3/2 back into y = -2x + 3:
y = -2(3/2) + 3
=> y = -3 + 3
=> y = 0
Therefore, the solution to the equation is x = 3/2 and y = 0.