1: 7sin^2x+5sinx-2=0 2: 5sin^2x-21cosx-9=0 3: 5tgx -6ctgx+7=0 4: 4cosx+sinx=0 5: sin^2x-6sinx=0 6: cos6x+cos4x=0 7: sin2x-2sin x=0 8: 3sin2x+2sin^2x=0 9: 7cos2x+18sin^2x-9=0 10: cos2x+11sin x-6=0

1 Апр 2019 в 19:45
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Ответы
1

1: This is a quadratic equation in terms of sin(x): 7(sin(x))^2 + 5sin(x) - 2 = 0. You can solve this by letting sin(x) = u and then solving for u, and then finding the corresponding x values.

2: This is a quadratic equation with both sin(x) and cos(x) terms. You can use the Pythagorean identity sin^2(x) + cos^2(x) = 1 to express everything in terms of sin(x) or cos(x), and then proceed to solve.

3: This is a quadratic equation in terms of tangent and cotangent. You can rewrite tan(x) as sin(x)/cos(x) and cot(x) as cos(x)/sin(x), and then solve as you would a regular quadratic equation.

4: This is a trigonometric equation with both cosine and sine terms. You can use the Pythagorean identity sin^2(x) + cos^2(x) = 1 to express everything in terms of one trigonometric function, and then solve.

5: This is a quadratic equation in terms of sin(x). Factor out sin(x) to solve for the values of x.

6: This equation involves both cosine terms. You can use the sum-to-product identity to simplify the equation and then solve for x.

7: Factor out sin(2x) to simplify the equation and solve for the values of x.

8: This equation involves both sine and cosine terms. Rewrite the equation in terms of only one trigonometric function and then solve.

9: This equation involves both cosine and sine terms. Use the Pythagorean identity to simplify the equation and then proceed to solve.

10: This equation involves both cosine and sine terms. Rewrite the equation in terms of only one trigonometric function and then solve.

28 Мая 2024 в 19:49
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