Let's first expand the expression on the left side:

(√3−2)^(2) = (√3−2) * (√3−2) = 3 - 2√3 - 2√3 + 4 = 7 - 4√3

Now let's expand the expression on the right side:

(√3−5)(√3−1) = √3 √3 - √3 1 - 5 * √3 + 5 = 3 - √3 - 5√3 + 5 = 8 - 6√3

Now we can subtract the two expressions:

(7 - 4√3) - (8 - 6√3) = 7 - 4√3 - 8 + 6√3 = -1 + 2√3

Therefore, (√3−2)^(2)−(√3−5)(√3−1) = -1 + 2√3.