To solve this system of equations, we can use the substitution method.
From the first equation, we can simplify it to:
x² + xy = 20.
We can now substitute this expression in the second equation:
(20) + 2y² = 14
Solving for y²:
y² = (14 - 20)/2y² = -6/2y² = -3y = √(-3)
Since the square root of a negative number is imaginary, there are no real solutions to this system of equations.
To solve this system of equations, we can use the substitution method.
From the first equation, we can simplify it to:
x² + xy = 20.
We can now substitute this expression in the second equation:
(20) + 2y² = 14
Solving for y²:
y² = (14 - 20)/2
y² = -6/2
y² = -3
y = √(-3)
Since the square root of a negative number is imaginary, there are no real solutions to this system of equations.