To solve this quadratic equation, we can first rearrange it into standard form:
-2x^2 + 5x + 3 = 0
Next, we can use the quadratic formula to find the roots of the equation. The quadratic formula states that for an equation in the form ax^2 + bx + c = 0, the roots are given by:
x = (-b ± √(b^2 - 4ac)) / 2a
In this case, a = -2, b = 5, and c = 3. Plugging these values into the formula, we get:
x = (-5 ± √(5^2 - 4(-2)(3))) / 2(-2) x = (-5 ± √(25 + 24)) / -4 x = (-5 ± √49) / -4 x = (-5 ± 7) / -4
This gives us two possible roots:
x = (-5 + 7) / -4 = 2 / -4 = -0.5
x = (-5 - 7) / -4 = -12 / -4 = 3
Therefore, the roots of the equation 3 - 2x^2 + 5x = 0 are x = -0.5 and x = 3.
To solve this quadratic equation, we can first rearrange it into standard form:
-2x^2 + 5x + 3 = 0
Next, we can use the quadratic formula to find the roots of the equation. The quadratic formula states that for an equation in the form ax^2 + bx + c = 0, the roots are given by:
x = (-b ± √(b^2 - 4ac)) / 2a
In this case, a = -2, b = 5, and c = 3. Plugging these values into the formula, we get:
x = (-5 ± √(5^2 - 4(-2)(3))) / 2(-2)
x = (-5 ± √(25 + 24)) / -4
x = (-5 ± √49) / -4
x = (-5 ± 7) / -4
This gives us two possible roots:
x = (-5 + 7) / -4 = 2 / -4 = -0.5
x = (-5 - 7) / -4 = -12 / -4 = 3
Therefore, the roots of the equation 3 - 2x^2 + 5x = 0 are x = -0.5 and x = 3.