2x+2yx+2yx+2y - 7y = 62x + 4y - 7y = 62x - 3y = 6y = 2x−62x - 62x−6 / 3
52x+y2x+y2x+y - x = 2y + 6010x + 5y - x = 2y + 609x + 3y = 603y = 60 - 9xy = 60−9x60 - 9x60−9x / 3y = 20 - 3x
Now we can substitute the value of y from the first equation into the second equation:
2x−62x - 62x−6 / 3 = 20 - 3x2x - 6 = 60 - 9x2x + 9x = 60 + 611x = 66x = 66 / 11x = 6
Now we can substitute the value of x back into the first equation to find y:
y = 2(6)−62(6) - 62(6)−6 / 3y = 12−612 - 612−6 / 3y = 6 / 3y = 2
So, the solution to the system of equations is x = 6 and y = 2.
2x+2yx+2yx+2y - 7y = 6
2x + 4y - 7y = 6
2x - 3y = 6
y = 2x−62x - 62x−6 / 3
52x+y2x+y2x+y - x = 2y + 60
10x + 5y - x = 2y + 60
9x + 3y = 60
3y = 60 - 9x
y = 60−9x60 - 9x60−9x / 3
y = 20 - 3x
Now we can substitute the value of y from the first equation into the second equation:
2x−62x - 62x−6 / 3 = 20 - 3x
2x - 6 = 60 - 9x
2x + 9x = 60 + 6
11x = 66
x = 66 / 11
x = 6
Now we can substitute the value of x back into the first equation to find y:
y = 2(6)−62(6) - 62(6)−6 / 3
y = 12−612 - 612−6 / 3
y = 6 / 3
y = 2
So, the solution to the system of equations is x = 6 and y = 2.