To find the limit of (sin x)/(tan(4x)) as x approaches 0, we can use L'Hôpital's Rule.
Using L'Hôpital's Rule:
lim (x→0) (sin x)/(tan(4x))= lim (x→0) cos x / (4sec^2(4x))= cos(0)/(4sec^2(0))= 1/(4*1)= 1/4
Therefore, the limit of (sin x)/(tan(4x)) as x approaches 0 is 1/4.
To find the limit of (sin x)/(tan(4x)) as x approaches 0, we can use L'Hôpital's Rule.
Using L'Hôpital's Rule:
lim (x→0) (sin x)/(tan(4x))
= lim (x→0) cos x / (4sec^2(4x))
= cos(0)/(4sec^2(0))
= 1/(4*1)
= 1/4
Therefore, the limit of (sin x)/(tan(4x)) as x approaches 0 is 1/4.