1)
To solve the inequality |3x - 5| > 10, we will break it down into two cases:

Case 1: 3x - 5 > 10
3x > 15
x > 5

Case 2: -(3x - 5) > 10
-3x + 5 > 10
-3x > 5
x < -5/3

Therefore, the solution to the inequality |3x - 5| > 10 is x < -5/3 or x > 5.

2)
To solve the inequality |x - 6| < x^2 - 5x + 9, we will break it down into two cases:

Case 1: x - 6 < x^2 - 5x + 9
x^2 - 6x - 3 < 0
(x - 3)(x + 1) < 0
-1 < x < 3

Case 2: -(x - 6) < x^2 - 5x + 9

x + 6 < x^2 - 5x + 9
x^2 - 4x + 3 > 0
(x - 3)(x - 1) > 0
x < 1 or x > 3

Therefore, the solution to the inequality |x - 6| < x^2 - 5x + 9 is -1 < x < 1 or 3 < x.