To solve the equations:

(3x+7)(x2-4) = 0

Set each factor to zero:
3x+7 = 0 → 3x = -7 → x = -7/3
x2-4 = 0 → x2 = 4 → x = ±2

Therefore, the solutions are x = -7/3, 2, -2.

x2 - 4x - 5 = 0

Using the quadratic formula:
x = (-(-4) ± √((-4)2 - 4(1)(-5)) / 2(1)
x = (4 ± √(16 + 20)) / 2
x = (4 ± √36) / 2
x = (4 ± 6) / 2

x = (4 + 6) / 2 or x = (4 - 6) / 2
x = 10 / 2 or x = -2 / 2
x = 5 or x = -1

Therefore, the solutions are x = 5, -1.

x2 - 3x = 0

Factor the equation: x(x - 3) = 0Set each factor to zero: x = 0 or x - 3 = 0 → x = 3

Therefore, the solutions are x = 0, 3.