The sum of the arcsine of -√3/2 and the arccotangent of 1/√3 can be simplified as follows:
1) Arcos(-√3/2) = π/62) Arcctg(1/√3) = arctan(√3) = π/3
Therefore, Arcos(-√3/2) + Arcctg(1/√3) = π/6 + π/3 = 2π/6 + 4π/6 = 6π/6 = π
So the correct answer is 1) π/6
The sum of the arcsine of -√3/2 and the arccotangent of 1/√3 can be simplified as follows:
1) Arcos(-√3/2) = π/6
2) Arcctg(1/√3) = arctan(√3) = π/3
Therefore, Arcos(-√3/2) + Arcctg(1/√3) = π/6 + π/3 = 2π/6 + 4π/6 = 6π/6 = π
So the correct answer is 1) π/6