To find the value of x, we can rewrite the equation sin2x + sin4x = sin6x as:

sin2x + 2sin2xcos2x = 2sin3xcos3x

Now, we can use the double angle identity for sine and the product-to-sum identity for sine to simplify the equation further:

2sin2xcos2x = 2sin3x(4cos3x - 3cos3x)
2sin2xcos2x = 2sin3x(4(1 - sin^2(3x)) - 3cos3x)
2sin2xcos2x = 2sin3x(4 - 4sin^2(3x) - 3cos3x)
2sin2xcos2x = 2sin3x(4 - 4sin^2(3x) - 3√(1 - sin^2(3x))^2)
2sin2xcos2x = 2sin3x(4 - 4sin^2(3x) - 3√(1 - sin^2(3x))^2)

After simplifying the equation, we get:

2sin2xcos2x = 2sin3x(4 - 4sin^2(3x) - 3√(1 - sin^2(3x))^2)

Therefore, the value of x cannot be determined from the given equation sin2x + sin4x = sin6x.