To solve this equation, we need to isolate the expression (3x + 19) inside the logarithm.
First, rewrite the equation using the exponential form of logarithm:5^2 = 3x + 19
Simplify the exponential expression:25 = 3x + 19
Subtract 19 from both sides:6 = 3x
Divide by 3 to solve for x:x = 2
Therefore, the solution to the equation Log5(3x + 19) = 2 is x = 2.
To solve this equation, we need to isolate the expression (3x + 19) inside the logarithm.
First, rewrite the equation using the exponential form of logarithm:
5^2 = 3x + 19
Simplify the exponential expression:
25 = 3x + 19
Subtract 19 from both sides:
6 = 3x
Divide by 3 to solve for x:
x = 2
Therefore, the solution to the equation Log5(3x + 19) = 2 is x = 2.