Г) log2(x) > 2
x > 2^2
x > 4

Д) log0.2(x+2) ≥ -1
x + 2 ≥ 0.2^-1
x + 2 ≥ 5
x ≥ 3

Е) 4^(x+2) - 134^x > 12
4^2 4^x - 134^x > 12
16 4^x - 13 4^x > 12
3 4^x > 12
4^x > 4
x > 1

Ж) lg^2(x) - lg(x) - 2 < 0
(log(x))^2 - log(x) - 2 < 0
Let y = log(x) then the inequality becomes:
y^2 - y - 2 < 0
(y - 2)(y + 1) < 0
-1 < y < 2
-1 < log(x) < 2
0 < x < 10^2
0 < x < 100

Ответ:
Г) x > 4
Д) x ≥ 3
Е) x > 1
Ж) 0 < x < 100