To find the value of the inductance (L), we can use the formula for the resonant frequency of an LC circuit:

f_res = 1 / (2 π √(L * C))

Given that the capacitance (C) is 50μF and the resonant frequency (f_res) is 5000 Hz (which is the same as 5000 kHz), we need to solve for the inductance (L):

5000 = 1 / (2 π √(L 5010^(-6)))

Solving for L:

5000 = 1 / (2 π √(L 5010^(-6)))
5000 = 1 / (2π√(5010^(-6)L))
5000 = 1 / (2 π √(5010^(-6)L))
5000 = 1 / (2 3.14159 (0.00005L)^(1/2))
5000 = 1 / (6.28318 (0.00005L)^(1/2))
5000 = 1 / (6.28318 (0.00005L)^(1/2))
5000 = 1 / (0.000314385 (0.00005L)^(1/2))
5000 = 1 / (0.000314385 (0.00005L)^(1/2))
5000 = 1 / 0.00001571925 (0.00005L)^(1/2)
5000 = 63.662481 (0.00005L)^(1/2)
5000 = √0.00005L 63.662481
0.0003165000 = √0.00005L
1.58 = 0.00707L
L = 223.0H

Therefore, the inductance of the circuit is 223.0H.