The reaction of 3-methylpentane-2 with HBr and KOH would result in the formation of 3-bromopentane-2.
The HBr would add a bromine atom to the second carbon of the 3-methylpentane, resulting in the formation of 3-bromopentane. The KOH would then act as a base to deprotonate the hydrogen from the bromine atom, resulting in the formation of the final product, 3-bromopentane-2.
The reaction of 3-methylpentane-2 with HBr and KOH would result in the formation of 3-bromopentane-2.
The HBr would add a bromine atom to the second carbon of the 3-methylpentane, resulting in the formation of 3-bromopentane. The KOH would then act as a base to deprotonate the hydrogen from the bromine atom, resulting in the formation of the final product, 3-bromopentane-2.