The reaction of CH3-CH2-C$0$-OH with NaOH will result in the formation of a sodium salt of the carboxylic acid and water. The reaction can be represented as follows:

CH3-CH2-C$0$-OH + NaOH → CH3-CH2-C$0$-ONa + H2O

When CH3OH is added to the resulting solution, it can protonate the carboxylate ion to form the carboxylic acid back:

CH3-CH2-C$0$-ONa + CH3OH → CH3-CH2-C$0$-OH + NaCH3O

Overall, the reaction will generate sodium methoxide and the carboxylic acid CH3-CH2-C$0$-OH.