1) MrAl(OH)3Al(OH)3Al(OH)3 = ArAlAlAl + 3*Ar(O)+Ar(H)Ar(O) + Ar(H)Ar(O)+Ar(H) = 27 + 3*16+116+116+1 = 78
ωOOO = 3∗Ar(O)/Mr(Al(OH)3)3*Ar(O)/Mr(Al(OH)3)3∗Ar(O)/Mr(Al(OH)3)*100% = 3∗16/783*16/783∗16/78*100% ≈ 61,54%
2) MrKOHKOHKOH = ArKKK + ArOOO + ArHHH = 39 + 16 + 1 = 56
ωOOO = Ar(O)/Mr(KOH)Ar(O)/Mr(KOH)Ar(O)/Mr(KOH)*100% = 16/5616/5616/56*100% ≈ 28,57%
3) MrBa(OH)2Ba(OH)2Ba(OH)2 = ArBaBaBa + 2*Ar(O)+Ar(H)Ar(O) + Ar(H)Ar(O)+Ar(H) = 137 + 2*16+116+116+1 = 171
ωOOO = 2∗Ar(O)/Mr(Ba(OH)2)2*Ar(O)/Mr(Ba(OH)2)2∗Ar(O)/Mr(Ba(OH)2)*100% = 2∗16/1712*16/1712∗16/171*100% ≈ 18,71%
1) MrAl(OH)3Al(OH)3Al(OH)3 = ArAlAlAl + 3*Ar(O)+Ar(H)Ar(O) + Ar(H)Ar(O)+Ar(H) = 27 + 3*16+116+116+1 = 78
ωOOO = 3∗Ar(O)/Mr(Al(OH)3)3*Ar(O)/Mr(Al(OH)3)3∗Ar(O)/Mr(Al(OH)3)*100% = 3∗16/783*16/783∗16/78*100% ≈ 61,54%
2) MrKOHKOHKOH = ArKKK + ArOOO + ArHHH = 39 + 16 + 1 = 56
ωOOO = Ar(O)/Mr(KOH)Ar(O)/Mr(KOH)Ar(O)/Mr(KOH)*100% = 16/5616/5616/56*100% ≈ 28,57%
3) MrBa(OH)2Ba(OH)2Ba(OH)2 = ArBaBaBa + 2*Ar(O)+Ar(H)Ar(O) + Ar(H)Ar(O)+Ar(H) = 137 + 2*16+116+116+1 = 171
ωOOO = 2∗Ar(O)/Mr(Ba(OH)2)2*Ar(O)/Mr(Ba(OH)2)2∗Ar(O)/Mr(Ba(OH)2)*100% = 2∗16/1712*16/1712∗16/171*100% ≈ 18,71%