n$NH3$ = V$NH3$/Vm = N$NH3$/Na

N$NH3$ = V$NH3$*Na/Vm

N1$H$ = 3*N$NH3$ = 3*V$NH3$*Na/Vm

N2$H$ = N1$H$

N$H2S$ = N2$H$/2 = $3\ast V(NH3)\ast Na$/$2\ast Vm$

n$H2S$ = V$H2S$/Vm = N$H2S$/Na

V$H2S$ = N$H2S$*Vm/Na = $3\ast V(NH3)\ast Na$/$2\ast Vm$*Vm/Na = $3/2$*V$NH3$ = $3/2$*22,4 = 33,6$л$

Ответ: V$H2S$ = 33,6 л