The formula provided is for iron $III$ chloride, so the breakdown of elements is as follows:

Fe - Iron
Cl - Chlorine

However, the formula states that the mass is 67 grams, so we can calculate the molar mass of FeCl₃ as follows:

Fe: 1 atom x 55.85 g/mol = 55.85 g/mol
Cl: 3 atoms x 35.45 g/mol = 106.35 g/mol

Total molar mass of FeCl₃ = 55.85 + 106.35 = 162.20 g/mol

Using the formula m = n * M, where m is the mass, n is the number of moles, and M is the molar mass, we can calculate the number of moles as follows:

n = m / M
n = 67 g / 162.20 g/mol ≈ 0.41 mol

Therefore, in 67 grams of FeCl₃, there are approximately 0.41 moles of the compound.