(x-3)^2 - 5 = x(x+2)
Expanding the left side:(x-3)(x-3) - 5= x^2 - 3x - 3x + 9 - 5= x^2 - 6x + 4
Setting the equation equal to the right side:x(x+2)= x^2 + 2x
Now equate the two sides:x^2 - 6x + 4 = x^2 + 2x
Subtract x^2 from both sides:-6x + 4 = 2x
Add 6x to both sides:4 = 8x
Divide by 8:x = 0.5
Therefore, the solution to the equation is x = 0.5.
(x-3)^2 - 5 = x(x+2)
Expanding the left side:
(x-3)(x-3) - 5
= x^2 - 3x - 3x + 9 - 5
= x^2 - 6x + 4
Setting the equation equal to the right side:
x(x+2)
= x^2 + 2x
Now equate the two sides:
x^2 - 6x + 4 = x^2 + 2x
Subtract x^2 from both sides:
-6x + 4 = 2x
Add 6x to both sides:
4 = 8x
Divide by 8:
x = 0.5
Therefore, the solution to the equation is x = 0.5.