Решить системы уравнений 1. у=х-2 4х+у=5
2. х=-2у х+у=4
3. у=4х х+2у=3
Решить системы уравнений 1. у=х-2 4х+у=5
2. х=-2у х+у=4
3. у=4х х+2у=3
2. х=-2у х+у=4
3. у=4х х+2у=3
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4x + y = 5
Substitute the value of y from the first equation into the second equation:
4x + x - 2 = 5
5x - 2 = 5
5x = 7
x = 7/5
Now substitute the value of x back into the first equation to find y:
y = 7/5 - 2
y = 7/5 - 10/5
y = -3/5
Therefore, the solution to the first system of equations is x = 7/5 and y = -3/5.
x = -2yx + y = 4
Substitute the value of x from the first equation into the second equation:
-2y + y = 4
-y = 4
y = -4
Now substitute the value of y back into the first equation to find x:
x = -2−4-4−4 x = 8
Therefore, the solution to the second system of equations is x = 8 and y = -4.
y = 4xx + 2y = 3
Substitute the value of y from the first equation into the second equation:
x + 24x4x4x = 3
x + 8x = 3
9x = 3
x = 1/3
Now substitute the value of x back into the first equation to find y:
y = 41/31/31/3 y = 4/3
Therefore, the solution to the third system of equations is x = 1/3 and y = 4/3.