To solve the given equation, we can rewrite it as:

sqrt$3$*sin$x$/4 - cos$x$/4 = 0

Now, we can rewrite it as:

sqrt$3$*sin$x$ = cos$x$

Now, we can square both sides to eliminate the square root:

3*sin^2$x$ = cos^2$x$

Using the trigonometric identity cos^2$x$ + sin^2$x$ = 1, we get:

3 - 3*cos^2$x$ = cos^2$x$

Expanding the equation:

3 = 4*cos^2$x$

Dividing both sides by 4:

3/4 = cos^2$x$

Taking the square root of both sides:

cos$x$ = ±sqrt$3$/2

Therefore, the solutions for x are:

x = π/6 + 2nπ, 5π/6 + 2nπ, where n is an integer.