Let's simplify the given equations and solve the system of equations.

1) 6(x+y) = 5 - (2x+y)
6x + 6y = 5 - 2x - y
8x + 7y = 5

2) 3x - 2y = -3y - 3
3x + y = -3

Now we have a system of two equations:

1) 8x + 7y = 5
2) 3x + y = -3

Let's solve this system using substitution or elimination method.

From equation 2,
y = -3 - 3x

Substitute y = -3 - 3x into equation 1:

8x + 7(-3 - 3x) = 5
8x - 21 - 21x = 5
-13x = 26
x = -2

Now substitute x = -2 into equation 2:

3(-2) + y = -3
-6 + y = -3
y = -3 + 6
y = 3

Therefore, the solution to the system of equations is x = -2 and y = 3.