To solve this system of equations, we can use the method of substitution. Let's first solve the first and third equations for x and y:
1) x + y - 4 = 0 2) -x - y + 6 = 0
From equation 1: x = 4 - y
Substitute x in equation 2: -(4 - y) - y + 6 = 0 -4 + y - y + 6 = 0 -2 = 0 This does not have a solution, so the system of equations is inconsistent and has no solution.
To solve this system of equations, we can use the method of substitution. Let's first solve the first and third equations for x and y:
1) x + y - 4 = 0
2) -x - y + 6 = 0
From equation 1:
x = 4 - y
Substitute x in equation 2:
-(4 - y) - y + 6 = 0
-4 + y - y + 6 = 0
-2 = 0
This does not have a solution, so the system of equations is inconsistent and has no solution.