Log15 log5 log2(32) = log15(log5(log2(32)))

First, we solve for log2(32):
log2(32) = log2(2^5)
= 5

Next, we find log5(log2(32)):
= log5(5)
= 1

Finally, we calculate log15(log5(log2(32))):
= log15(1)
= 0

Therefore, log15 log5 log2(32) = 0.