Let's expand the left side of the equation first:

$x+3$$x-2$ = x^2 + x$-2$ + 3x - 6
$x-3$$x+2$ = x^2 + x$2$ - 3x - 6

Now, we can rewrite the original equation with the expansions:

$x^2+x-6$ - $x^2+2x-3x-6$ - 5 = 6x - y

Simplify the equation:

x - 6 - x^2 - 2x + 3x + 6 - 5 = 6x - y
x - x^2 - 2x + 3x - 5 = 6x - y
-x^2 + 2x - 5 = 6x - y

Rearrange terms to get the equation in the standard form:

-x^2 + 2x - 5 - 6x + y = 0
-x^2 - 4x - 5 + y = 0

Therefore, the simplified equation is -x^2 - 4x - y - 5 = 0.