Пусть AB=BC=CD=DE=EF=a. Тогда AC=AB+BC=2a, AD=AB+BC+CD=3a, AE=AB+BC+CD+DE=4a, AF=AB+BC+CD+DE+EF=5a.
1) AD:DF = 3a:a = 3:1.2) AC:AF = 2a:5a = 2:5.3) BD:CE = BC:CD = a:a = 1:1.4) BF:BD = BF:BC = 2a:a = 2:1.
Пусть AB=BC=CD=DE=EF=a. Тогда AC=AB+BC=2a, AD=AB+BC+CD=3a, AE=AB+BC+CD+DE=4a, AF=AB+BC+CD+DE+EF=5a.
1) AD:DF = 3a:a = 3:1.
2) AC:AF = 2a:5a = 2:5.
3) BD:CE = BC:CD = a:a = 1:1.
4) BF:BD = BF:BC = 2a:a = 2:1.