Expanding the left side of the equation:

(2x-3)^2 = (2x-3)(2x-3) = 4x^2 - 12x + 9

(2x-1)(2x+3) = 2x2x + 2x3 - 12x - 1*3 = 4x^2 + 6x - 2x - 3 = 4x^2 + 4x - 3

Adding the two expanded terms together:

(2x-3)^2 + (2x-1)*(2x+3) = 4x^2 - 12x + 9 + 4x^2 + 4x - 3
= 8x^2 - 8x + 6

Since this equals 4, we can now set up the equation:

8x^2 - 8x + 6 = 4

Subtract 4 from both sides:

8x^2 - 8x + 6 - 4 = 0
8x^2 - 8x + 2 = 0

Divide by 2 to simplify:

4x^2 - 4x + 1 = 0

This is the final equation.