To find the value of "a", we need to expand the right side of the equation and compare it to the left side.
Given: x^2 + 6x - 27 = (x + 9)(x - a)
Expanding the right side:(x + 9)(x - a) = x^2 - ax + 9x - 9a= x^2 + (9-a)x - 9a
Comparing the expanded right side to the left side:x^2 + 6x - 27 = x^2 + (9-a)x - 9a
To find the value of "a", we compare the coefficients of the terms:6x = (9-a)x, and -27 = -9a
From the first equation:6 = 9 - aa = 9 - 6a = 3
Therefore, a = 3.
To find the value of "a", we need to expand the right side of the equation and compare it to the left side.
Given: x^2 + 6x - 27 = (x + 9)(x - a)
Expanding the right side:
(x + 9)(x - a) = x^2 - ax + 9x - 9a
= x^2 + (9-a)x - 9a
Comparing the expanded right side to the left side:
x^2 + 6x - 27 = x^2 + (9-a)x - 9a
To find the value of "a", we compare the coefficients of the terms:
6x = (9-a)x, and -27 = -9a
From the first equation:
6 = 9 - a
a = 9 - 6
a = 3
Therefore, a = 3.