Next, we subtract 24 from both sides to set the equation to zero:
x^3 + 6035x^2 + 6072011x + 4076180 = 0
Now we can look for the roots of this equation. One possible root can be found by trial and error; plugging in small integers as potential solutions.
By trying x = -2, we find that it is a root of the equation. Therefore, we can factor out x+2x+2x+2 and perform polynomial division to find the other roots:
To solve this equation, we first need to expand the left side of the equation:
x+2014x+2014x+2014x+2015x+2015x+2015x+2016x+2016x+2016 = x^3 + 6035x^2 + 6072011x + 4076204
Now we set this expression equal to 24:
x^3 + 6035x^2 + 6072011x + 4076204 = 24
Next, we subtract 24 from both sides to set the equation to zero:
x^3 + 6035x^2 + 6072011x + 4076180 = 0
Now we can look for the roots of this equation. One possible root can be found by trial and error; plugging in small integers as potential solutions.
By trying x = -2, we find that it is a root of the equation. Therefore, we can factor out x+2x+2x+2 and perform polynomial division to find the other roots:
x+2x+2x+2x2+6033x+2038090x^2 + 6033x + 2038090x2+6033x+2038090 = 0
Setting x^2 + 6033x + 2038090 = 0, we can use the quadratic formula:
x = −6033±sqrt(60332−4<em>1</em>2038090)-6033 ± sqrt(6033^2 - 4<em>1</em>2038090)−6033±sqrt(60332−4<em>1</em>2038090) / 2
x = −6033±sqrt(36472489−8152360)-6033 ± sqrt(36472489 - 8152360)−6033±sqrt(36472489−8152360) / 2
x = −6033±sqrt(28320129)-6033 ± sqrt(28320129)−6033±sqrt(28320129) / 2
x = −6033±5320.40-6033 ± 5320.40−6033±5320.40 / 2
Therefore, the roots of the equation are -2, -3006.2, and -3026.8.