To solve this expression, we first need to evaluate each trigonometric function at the given angles:
Now we can substitute these values back into the expression:
2 sinπ/4π/4π/4 - 3 tgπ/6π/6π/6 + ctg−3π/2-3π/2−3π/2 - tgπππ = 2 √2 / 2 - 3 √3 + 0 - 0= √2 - 3√3
Therefore, the final result of the expression 2sinπ/4π/4π/4 - 3tgπ/6π/6π/6 + ctg−3π/2-3π/2−3π/2 - tgπππ is √2 - 3√3.
To solve this expression, we first need to evaluate each trigonometric function at the given angles:
sinπ/4π/4π/4 = √2 / 2tgπ/6π/6π/6 = √3ctg−3π/2-3π/2−3π/2 = - 0 ctgfunctionisundefinedat−3π/2ctg function is undefined at -3π/2ctgfunctionisundefinedat−3π/2tgπππ = 0Now we can substitute these values back into the expression:
2 sinπ/4π/4π/4 - 3 tgπ/6π/6π/6 + ctg−3π/2-3π/2−3π/2 - tgπππ = 2 √2 / 2 - 3 √3 + 0 - 0
= √2 - 3√3
Therefore, the final result of the expression 2sinπ/4π/4π/4 - 3tgπ/6π/6π/6 + ctg−3π/2-3π/2−3π/2 - tgπππ is √2 - 3√3.