To solve this equation, we can first rewrite both sides using the property of logarithms that states log(b,x) = log(b,y) if and only if x = y.
log0,3(13-x) = log0,3(x+3)
3^(log0,3(13-x)) = 3^(log0,3(x+3))
13 - x = x + 3
Now, we can solve for x:
13 - 3 = x + x
10 = 2x
x = 5
Therefore, the solution to the equation log0,3(13-x) = log0,3(x+3) is x = 5.
To solve this equation, we can first rewrite both sides using the property of logarithms that states log(b,x) = log(b,y) if and only if x = y.
log0,3(13-x) = log0,3(x+3)
3^(log0,3(13-x)) = 3^(log0,3(x+3))
13 - x = x + 3
Now, we can solve for x:
13 - 3 = x + x
10 = 2x
x = 5
Therefore, the solution to the equation log0,3(13-x) = log0,3(x+3) is x = 5.