To solve this equation, we first need to use the property of logarithms that states if log a bbb = log a ccc, then b = c.
So in this case,4x - 6 = 2x - 4
Solving for x, we get:4x - 2x = -4 + 62x = 2x = 1
Therefore, the solution to the equation log74x−64x-64x−6 = log72x−42x-42x−4 is x = 1.
To solve this equation, we first need to use the property of logarithms that states if log a bbb = log a ccc, then b = c.
So in this case,
4x - 6 = 2x - 4
Solving for x, we get:
4x - 2x = -4 + 6
2x = 2
x = 1
Therefore, the solution to the equation log74x−64x-64x−6 = log72x−42x-42x−4 is x = 1.