To solve this equation, we need to use the properties of logarithms.

First, we can simplify the equation using the properties of logarithms:

Log3x - 2Log(1/3)x = 6
Log3x - Log((1/3)x)^2 = 6
Log3x - Log(x^2/9) = 6
Log(3x / (x^2/9)) = 6
Log(27 / x) = 6

Now we can rewrite this equation in exponential form:

27 / x = 10^6
27 = 10^6 * x
27 = 1000000x
x = 27 / 1000000
x = 0.000027

Therefore, the solution to the equation Log3x - 2Log(1/3)x = 6 is x = 0.000027.