log_3 (27√3) = log_3 (27) + log_3 (√3)
= 3 + (1/2) = 3.5

log_2 (∛16) = log_2 (16^(1/3))
= (1/3) log_2 (16)
= (1/3) 4 = 4/3

Therefore, log_3 (27√3) + log_2 (∛16) = 3.5 + (4/3) = 10/3 ≈ 3.33.