To solve for the intersection point of the two equations, we set them equal to each other:
sin(2x) = 0
This equation will be satisfied when 2x = nπ, where n is an integer. Since the value of x is constrained to be between 0 and π/2, we can see that the only possible solution occurs when n = 0, in which case:
2x = 0
x = 0
Therefore, the intersection point of y = sin(2x) and y = 0 within the given interval is at x = 0.
To solve for the intersection point of the two equations, we set them equal to each other:
sin(2x) = 0
This equation will be satisfied when 2x = nπ, where n is an integer. Since the value of x is constrained to be between 0 and π/2, we can see that the only possible solution occurs when n = 0, in which case:
2x = 0
x = 0
Therefore, the intersection point of y = sin(2x) and y = 0 within the given interval is at x = 0.