To solve the equation 2x^2 - 2x + 2 = 0, we can use the quadratic formula:
x = (-(-2) ± √((-2)^2 - 4(2)(2))) / 2(2)x = (2 ± √(4 - 16)) / 4x = (2 ± √(-12)) / 4x = (2 ± 2√3i) / 4x = (1 ± √3i) / 2
Therefore, the solutions to the equation are x = 1 + √3i / 2 and x = 1 - √3i / 2.
To solve the equation 2x^2 - 2x + 2 = 0, we can use the quadratic formula:
x = (-(-2) ± √((-2)^2 - 4(2)(2))) / 2(2)
x = (2 ± √(4 - 16)) / 4
x = (2 ± √(-12)) / 4
x = (2 ± 2√3i) / 4
x = (1 ± √3i) / 2
Therefore, the solutions to the equation are x = 1 + √3i / 2 and x = 1 - √3i / 2.