To find the product of these two vectors, we need to perform scalar multiplication of the components of the vectors.
(-28 , 4−5 2\5) ⋅(-0,1 ) = -28 0 + (4 - 5/2) 1= 0 + (4 - 2.5)= 1.5
Therefore, the dot product of the vectors (-28 , 4−5 2\5) and (-0,1 ) is 1.5.
To find the product of these two vectors, we need to perform scalar multiplication of the components of the vectors.
(-28 , 4−5 2\5) ⋅(-0,1 ) = -28 0 + (4 - 5/2) 1
= 0 + (4 - 2.5)
= 1.5
Therefore, the dot product of the vectors (-28 , 4−5 2\5) and (-0,1 ) is 1.5.