To solve the given equation, we can first apply the properties of logarithms to get rid of the logarithms by using the fact that log(a) = log(b) implies that a = b.
Thus, we have: 7^(log7(2x-6)) = 7^(log7(x+1))
This simplifies to: 2x - 6 = x + 1
Now, we can solve for x by moving 1 to the other side: 2x - x = 6 + 1 x = 7
Therefore, the solution to the equation log7(2x-6) = log7(x+1) is x = 7.
To solve the given equation, we can first apply the properties of logarithms to get rid of the logarithms by using the fact that log(a) = log(b) implies that a = b.
Thus, we have:
7^(log7(2x-6)) = 7^(log7(x+1))
This simplifies to:
2x - 6 = x + 1
Now, we can solve for x by moving 1 to the other side:
2x - x = 6 + 1
x = 7
Therefore, the solution to the equation log7(2x-6) = log7(x+1) is x = 7.