First, let's move all terms to one side of the equation:
[x^{2}-2x+\sqrt{4-x}-\sqrt{4-x}-15=0]
Simplify:
[x^{2}-2x-15=0]
Now, we have a quadratic equation. We can factor it as:
[(x-5)(x+3)=0]
Therefore, the solutions are:
[x=5 \text{ or } x=-3]
First, let's move all terms to one side of the equation:
[x^{2}-2x+\sqrt{4-x}-\sqrt{4-x}-15=0]
Simplify:
[x^{2}-2x-15=0]
Now, we have a quadratic equation. We can factor it as:
[(x-5)(x+3)=0]
Therefore, the solutions are:
[x=5 \text{ or } x=-3]