To solve this equation, we can use the property of logarithms that states log a (x) = b is equivalent to x = a^b.

Therefore, we can rewrite the given equation as:

2(6x - 3) = 3x + 1

12x - 6 = 3x + 1

Simplify the equation:

12x - 3x = 1 + 6

9x = 7

Divide by 9:

x = 7/9

Therefore, the solution to the equation log2(6x-3) = log(3x+1) is x = 7/9.