To solve this cubic equation, we can try to factor it or use the rational root theorem to find a possible rational root.
Looking at the coefficients, we see that the possible rational roots are ±1, ±3, ±9. By trying these values, we find that x = 3 is a root of the equation.
Using synthetic division or polynomial long division, we divide the given equation by (x-3) to get:
(x^3 + x^2 - 9x - 9) / (x - 3) = x^2 + 4x + 3
Now, we have a quadratic equation x^2 + 4x + 3 = 0. This can be easily factored as (x + 1)(x + 3) = 0.
Therefore, the solutions to the cubic equation x^3 + x^2 - 9x - 9 = 0 are x = 3, x = -1, and x = -3.
To solve this cubic equation, we can try to factor it or use the rational root theorem to find a possible rational root.
Looking at the coefficients, we see that the possible rational roots are ±1, ±3, ±9. By trying these values, we find that x = 3 is a root of the equation.
Using synthetic division or polynomial long division, we divide the given equation by (x-3) to get:
(x^3 + x^2 - 9x - 9) / (x - 3) = x^2 + 4x + 3
Now, we have a quadratic equation x^2 + 4x + 3 = 0. This can be easily factored as (x + 1)(x + 3) = 0.
Therefore, the solutions to the cubic equation x^3 + x^2 - 9x - 9 = 0 are x = 3, x = -1, and x = -3.