(2+i)(3-3i) = 23 + 2(-3i) + i3 + i(-3i)= 6 - 6i + 3i - 3i^2= 6 - 3i - 3(-1)= 6 - 3i + 3= 9 - 3i
Ответ: 9 - 3i
(2+i)(3-3i) = 23 + 2(-3i) + i3 + i(-3i)
= 6 - 6i + 3i - 3i^2
= 6 - 3i - 3(-1)
= 6 - 3i + 3
= 9 - 3i
Ответ: 9 - 3i