To find the derivative of the function f(x) = x(1 + cos(x)) at X = π, we can use the product rule and chain rule.
f'(x) = 1(1 + cos(x)) + x(-sin(x))= 1 + cos(x) - x*sin(x)
Now, to find f'(π), we substitute x = π into the derivative:
f'(π) = 1 + cos(π) - π*sin(π)= 1 + (-1) - 0= 0
Therefore, f'(π) = 0.
To find the derivative of the function f(x) = x(1 + cos(x)) at X = π, we can use the product rule and chain rule.
f'(x) = 1(1 + cos(x)) + x(-sin(x))
= 1 + cos(x) - x*sin(x)
Now, to find f'(π), we substitute x = π into the derivative:
f'(π) = 1 + cos(π) - π*sin(π)
= 1 + (-1) - 0
= 0
Therefore, f'(π) = 0.